Question

\sqrt{3} cos pi/6 sin (-pi/2)

Answer 1

√3cos pi/6 sin(-pi/2)=√3cos pi/6*(- sin(pi/2)=√3* √3/2*(-1)=  -3/2

Answer 2

Let's start by simplifying each of the trigonometric functions separately:

cos(pi/6) = √3/2 (using the values of cosine for 30 degrees or pi/6)

sin(-pi/2) = -1 (using the value of sine for 270 degrees or -pi/2)

Now, we can substitute these values into the original expression:

√3 cos(pi/6) sin(-pi/2) = √3/2 * (-1) = -√3/2

Therefore, the value of the expression is -√3/2.