Question

3х^2 - 5х - 2/ 2 - х = 0 3х^2 - 5х - 2/ 2 - х = 0 4/1 - 9у^2 + 3/ 3у^2 + у = 4/ 9у^2 + 6у + 1

Answer 1

Если там 3х квадрат то так

Answer 2

To solve the equations, let's simplify them and solve for the unknown variables.

Equation 1: (3x^2 - 5x - 2) / (2 - x) = 0

To solve this equation, we need to find the values of x that make the numerator equal to zero, while also ensuring that the denominator is not zero.

First, let's factor the numerator: 3x^2 - 5x - 2 = (3x + 1)(x - 2)

Now, we have the equation: (3x + 1)(x - 2) / (2 - x) = 0

To find the values of x, we set each factor equal to zero: 3x + 1 = 0 --> 3x = -1 --> x = -1/3 x - 2 = 0 --> x = 2

However, we also need to consider the denominator, which cannot be zero. Therefore, x ≠ 2.

So, the solution for Equation 1 is x = -1/3.

Equation 2: (4 / (1 - 9y^2)) + (3 / (3y^2 + y)) = (4 / (9y^2 + 6y + 1))

To solve this equation, let's find a common denominator for all the fractions involved, and then simplify the equation.

The common denominator is (1 - 9y^2)(3y^2 + y) = (1 - 3y)(1 + 3y)(3y^2 + y).

Multiplying all terms by this common denominator, we get: 4(3y^2 + y) + 3(1 - 3y)(1 + 3y) = 4(1 - 3y)(1 + 3y)

Expanding and simplifying the equation: 12y^2 + 4y + 3(1 - 9y^2) = 4(1 - 9y^2)

12y^2 + 4y + 3 - 27y^2 = 4 - 36y^2

Combine like terms: -15y^2 + 4y + 3 = -32y^2 + 4

Move all terms to one side to set the equation to zero: -15y^2 + 32y^2 + 4y + 3 - 4 = 0

Combine like terms again: 17y^2 + 4y - 1 = 0

This equation is a quadratic equation in the form of ay^2 + by + c = 0, where a = 17, b = 4, and c = -1.

To solve this quadratic equation, we can use the quadratic formula: y = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values into the formula, we have: y = (-(4) ± √((4)^2 - 4(17)(-1))) / (2(17))

Simplifying further: y = (-4 ± √(16 + 68)) / 34 y = (-4 ± √84) / 34

We can simplify the square root term by factoring out the largest perfect square: y = (-4 ± √(4 * 21)) / 34 y = (-4 ± 2√21) / 34 y = (-2 ± √21) / 17

So, the solutions for Equation 2 are: y = (-2