Question

(8y-12)(2,1+0,3y)=0 решить уравнение

Answer 1

(8y-12)(2.1+0.3y) =0

(8y-12)(21\10+3/10)=0

8y-12=0

21/10+3/10

y= 3/2

y1=-7      

Answer 2

To solve the equation (8y - 12)(2.1 + 0.3y) = 0, we can set each factor equal to zero and solve for y separately.

Setting the first factor, 8y - 12, equal to zero: 8y - 12 = 0 8y = 12 y = 12/8 y = 1.5

Now setting the second factor, 2.1 + 0.3y, equal to zero: 2.1 + 0.3y = 0 0.3y = -2.1 y = -2.1/0.3 y = -7

Therefore, the solutions to the equation (8y - 12)(2.1 + 0.3y) = 0 are y = 1.5 and y = -7.