Question

Lg(5) * lg(20) + lg^2(2) =?

Answer 1

$lg5(lg4+lg5)+lg^22=lg5*2lg2+lg^25+lg^22=(lg2+lg5)^2=l(g10)^2$=1

Answer 2

To solve this equation, let's break it down step by step:

1. Start by calculating the logarithms separately:

   • lg(5) ≈ 0.69897 (rounded to 5 decimal places)
   • lg(20) ≈ 1.30103 (rounded to 5 decimal places)
   • lg^2(2) = (lg(2))^2 ≈ 0.30103^2 ≈ 0.09062 (rounded to 5 decimal places)

2. Substitute the calculated values back into the equation: 0.69897 * 1.30103 + 0.09062 ≈ 0.90896 + 0.09062 ≈ 0.99958 (rounded to 5 decimal places)

Therefore, lg(5) * lg(20) + lg^2(2) ≈ 0.99958.