Question

1)x^2-6x=5=0 2)x^2 =4x-5=0 3)(4-x)(4=x)=x^2-2

Answer 1

x^2-6x+5=0

D=4b^2-4ac=-6^2-4*1*5=36-20=16

VD = V16 = 4

        - b+ - VD

x = -----------------

             2a

 

x1 = (6+4)/2 = 10/2=5

x2 = (6-4)/2 = 2/2=1

 

OTBET: x=1 i x=5

 

 

 

 

x^2 +4x-5=0

D = 4^2-4*1*-5 = 16- (-20) = 16+20 = 36

VD = V36 = 6

x1 = (-4+6)/2 = 2/2 = 1

x2 = (-4-6)/2 = -10/2 = -5

 

OTBET:  x=-5 i x=1

 

 

 

(4-x)(4+x)=x^2-2

16+4x-4x-x^2 = x^2-2

16+4x-4x-x^2- x^2+2 =0

-2x^2+18=0   / :(-2)

x^2 = 9

 x= + - 3

 

кажется,так.... :)

 

 

 

Answer 2

It seems like you have provided three equations, but there are some formatting issues. Let's try to correct them and solve the equations one by one:

1. $x^2 - 6x + 5 = 0$: To solve this quadratic equation, we can use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

For the given equation, the coefficients are: $a = 1$, $b = -6$, and $c = 5$.

Substituting these values into the quadratic formula, we get: $x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(1)(5)}}{2(1)}$ Simplifying this equation further: $x = \frac{6 \pm \sqrt{36 - 20}}{2}$ $x = \frac{6 \pm \sqrt{16}}{2}$ $x = \frac{6 \pm 4}{2}$

This results in two possible solutions: $x_1 = \frac{6 + 4}{2} = 5$ $x_2 = \frac{6 - 4}{2} = 1$

Therefore, the solutions to the equation are $x = 5$ and $x = 1$.

2. $x^2 = 4x - 5 = 0$: Again, there seems to be an issue with the formatting of the equation. Let's assume it is $x^2 - 4x - 5 = 0$.

To solve this quadratic equation, we can use the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

For the given equation, the coefficients are: $a = 1$, $b = -4$, and $c = -5$.

Substituting these values into the quadratic formula, we get: $x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(-5)}}{2(1)}$ Simplifying this equation further: $x = \frac{4 \pm \sqrt{16 + 20}}{2}$ $x = \frac{4 \pm \sqrt{36}}{2}$ $x = \frac{4 \pm 6}{2}$

This results in two possible solutions: $x_1 = \frac{4 + 6}{2} = 5$ $x_2 = \frac{4 - 6}{2} = -1$

Therefore, the solutions to the equation are $x = 5$ and $x = -1$.

3. $(4 - x)(4 = x) = x^2 - 2$: The equation you provided seems to have formatting issues. It's unclear how to interpret it. Could you please provide the correct equation?