Question

(7-2x-x²)-(x-2)(x+3)

Answer 1

= 7-2х-х²-(х²+3х-2х-6) = 7-2х-х²-х²-х+6 = -2х²-3х+13

Answer 2

To simplify the expression (7-2x-x²)-(x-2)(x+3), let's start by expanding the second term, which is (x-2)(x+3):

(x-2)(x+3) = x(x+3) - 2(x+3) = x^2 + 3x - 2x - 6 = x^2 + x - 6

Now, let's substitute this result back into the original expression and simplify further:

(7-2x-x²) - (x^2 + x - 6)

To subtract these expressions, distribute the negative sign to every term within the parentheses:

7 - 2x - x^2 - x^2 - x + 6

Combine like terms:

(-x^2 - x^2) + (-2x - x) + (7 + 6) -2x^2 - 3x + 13

So, the simplified form of (7-2x-x²)-(x-2)(x+3) is -2x^2 - 3x + 13.