
1)cosa*cos3a-sina*sin3a 2) sin2a*cosa+cos2a*sina 3) sin40*cos5+cos40*sin5 4)
(tg7П/15-tg2П/15)/1+tg7П/15*tg2П/15 5) sina=4/5;П<a<3П/2; cosa-?

Ответы на вопрос

1) cos a cos 3a - sin a sin 3a = cos (a+3a) = cos 4a
2) sin 2a cos a + cos 2a sin a = sin (2a+a) = sin 3a
3) sin40°cos5°+cos40°sin5° = sin(40°+5°)= sin 45° =
4)
5)




- To simplify the expression cosacos3a - sinasin3a, we can use the trigonometric identity for the cosine of the difference of angles:
cosacos3a - sinasin3a = cos(a - 3a) = cos(-2a) = cos(2a)
So the simplified expression is cos(2a).
- Similarly, for the expression sin2acosa + cos2asina, we can use the trigonometric identity for the sine of the sum of angles:
sin2acosa + cos2asina = sin(2a + a) = sin(3a)
So the simplified expression is sin(3a).
- For the expression sin40cos5 + cos40sin5, we can rewrite it using the trigonometric identity for the sine of the sum of angles:
sin(40 + 5) = sin(45)
Since sin(45) is a known value, the simplified expression is sin(45) = 1/√2 or approximately 0.707.
- The expression (tg(7π/15) - tg(2π/15)) / (1 + tg(7π/15) * tg(2π/15)) can be simplified using the trigonometric identity for tangent of the difference of angles:
tg(7π/15) - tg(2π/15) = tg(7π/15 - 2π/15) = tg(5π/15) = tg(π/3) = √3
Similarly, using the trigonometric identity for tangent of the sum of angles:
1 + tg(7π/15) * tg(2π/15) = 1 + tg(7π/15 + 2π/15) = 1 + tg(9π/15) = 1 + tg(3π/5) = 1 + √3
Therefore, the simplified expression is (√3) / (1 + √3).
- Given that sina = 4/5 and π < a < (3π/2), we can determine the value of cosa using the Pythagorean identity:
cos^2(a) + sin^2(a) = 1
Replacing sin(a) with 4/5, we get:
cos^2(a) + (4/5)^2 = 1 cos^2(a) + 16/25 = 1 cos^2(a) = 1 - 16/25 cos^2(a) = 9/25
Taking the square root of both sides:
cos(a) = ±√(9/25) = ±3/5
Since a is in the range π < a < (3π/2), sin(a) is positive and cos(a) is negative. Therefore, cos(a) = -3/5.


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