Question

14. Определить (в кэВ) энергию кванта жесткого рентгеновского излучения (длина волны 1 Å).

Answer 1

E=h*c/L=6,62*10^-34*3*10^8/10^-10=19,86*10^-16 Дж=12,4*10^3 эВ=12,4 кэВ

Answer 2

Energy of Hard X-ray Quantum

To determine the energy of a hard X-ray quantum with a wavelength of 1 Å (angstrom), we can use the equation:

Energy (in keV) = 12.398 / Wavelength (in Å).

Substituting the given wavelength of 1 Å into the equation, we can calculate the energy:

Energy = 12.398 / 1 = 12.398 keV.

Therefore, the energy of a hard X-ray quantum with a wavelength of 1 Å is approximately 12.398 keV.

Please note that the calculation assumes the quantum is a photon and uses the relationship between energy and wavelength for electromagnetic radiation.