Question

Катушка диаметром 4 см находится в переменном магнитном поле, силовые линии которого параллельны оси катушки. При изменении индукции поля на 1 Тл в течение 6,28 с в катушке возникла ЭДС 2 В. Сколько витков имеет катушка?

Answer 1

Дано:
d=4*10^-2м
B=1Тл
t=6.28c
E=2B(ЭДС)
Найти: N-?
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Решение:
$E=-N* \frac{f }{t}$ где f- это ф(магнитный поток)
ф=BScosa
$S= \frac{ \pi * d^{2} }{4}$
Формулу берем по модулю!
$E=|- \frac{N* \pi * d^{2} }{4*t} |$ отсюда выводим что нам нужно найти N
$N= \frac{E*t*4}{ \pi * d^{2} }$
 В эту формулу подставляем дано!
УСПЕХОВ!

Answer 2

Calculation of the Number of Turns in the Coil

To calculate the number of turns in the coil, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force (EMF) in a coil is equal to the rate of change of magnetic flux through the coil.

The formula for calculating the induced EMF is:

EMF = -N * dΦ/dt

Where: - EMF is the induced electromotive force (in volts) - N is the number of turns in the coil - dΦ/dt is the rate of change of magnetic flux through the coil (in webers per second)

In this case, we are given that the induced EMF is 2 V and the rate of change of magnetic flux is 1 T/s. We need to find the number of turns in the coil.

Let's substitute the given values into the formula and solve for N:

2 V = -N * (1 T/s)

To solve for N, we can rearrange the equation:

N = -2 V / (1 T/s)

Simplifying further:

N = -2 V * (s/T)

Since the units of volts and teslas cancel out, we are left with:

N = -2 s

Therefore, the number of turns in the coil is -2.

It's important to note that the negative sign in the result indicates the direction of the induced EMF, which is opposite to the direction of the change in magnetic flux.

Please let me know if you need any further assistance!