Question

Вода, пролитая на стол, растеклась по нему тонким слоем толщиной 1,22 мм. Найдите площадь образовавшейся на столе лужи, если было пролито 50 г воды. Плотность воды 1,00 г/см3 . Ответ выразите в см2 , округлив до целого числа.

Answer 1

Дано m=50 г    p=1 г/см3    h=0,122 см    S- ?

1) V=m/p=50/1=50 см3

2) V=S*h    S=V/h=50/0,122=409,84 см2

Answer 2

Calculation of the Area of the Spilled Water

To find the area of the puddle formed on the table, we need to calculate the volume of the spilled water first. We are given that 50 grams of water was spilled. The density of water is 1.00 g/cm³.

The formula to calculate the volume is:

Volume = Mass / Density

Substituting the given values:

Volume = 50 g / 1.00 g/cm³

To convert the volume from cm³ to mm³, we need to multiply it by 1,000 since 1 cm³ is equal to 1,000 mm³.

Volume = (50 g / 1.00 g/cm³) * 1,000 = 50,000 mm³

Now, to find the area of the puddle, we need to divide the volume by the thickness of the water layer. The thickness of the water layer is given as 1.22 mm.

Area = Volume / Thickness

Substituting the values:

Area = 50,000 mm³ / 1.22 mm

Calculating this value gives us:

Area ≈ 40,983.61 mm²

Rounding this to the nearest whole number, the area of the puddle formed on the table is approximately 40,984 cm².

Please note that the provided sources do not contain relevant information for this specific calculation.