Question

Масса каждого из двух одинаковых сосудов , заполненных свинцовой дробью , равна 2100 Г .Когда в один из сосудов налили доверху воду , а в другой - неизвестную жидкость , масса сосудов стали соответственно 2200г и 2185г . Какова плотность неизвестной жидкости?

Answer 1

2.2-2.1=0.1кг это масса воды
V-воды=Vжидкости=m/v=0.1 100010^(-4)м^3p жидкости = (2.185-2.1)/V=1850кг/м^3...

Answer 2

Calculation of the Density of the Unknown Liquid

To calculate the density of the unknown liquid, we can use the principle of buoyancy. According to Archimedes' principle, the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

In this case, we have two identical vessels filled with lead shot. The mass of each vessel, when filled with lead shot, is 2100 g. When one of the vessels is filled to the brim with water, its mass becomes 2200 g. When the other vessel is filled with the unknown liquid, its mass becomes 2185 g.

To find the density of the unknown liquid, we need to compare the buoyant forces acting on the two vessels when they are submerged in their respective fluids.

Calculation Steps:

1. Calculate the weight of the water displaced by the vessel filled with water: - The weight of the water displaced is equal to the increase in mass of the vessel filled with water. - The increase in mass is 2200 g - 2100 g = 100 g. - The weight of the water displaced is 100 g.

2. Calculate the weight of the unknown liquid displaced by the vessel filled with the unknown liquid: - The weight of the unknown liquid displaced is equal to the increase in mass of the vessel filled with the unknown liquid. - The increase in mass is 2185 g - 2100 g = 85 g. - The weight of the unknown liquid displaced is 85 g.

3. Compare the weights of the water and the unknown liquid displaced: - The weight of the water displaced is 100 g. - The weight of the unknown liquid displaced is 85 g.

4. Calculate the density of the unknown liquid: - The density of a substance is equal to its mass divided by its volume. - Since the volume of the vessels is the same, we can compare the densities directly. - The density of the unknown liquid is 85 g / 100 g = 0.85.

Therefore, the density of the unknown liquid is 0.85 g/cm³.

Please note that the above calculation assumes that the vessels and the lead shot have negligible densities compared to the water and the unknown liquid.