Question

Помогитееее, физика! 1.С КАКОЙ СИЛОЙ ВЗАИМОДЕЙСТВУЕТ ДВА ЗАРЯДА 64нКл и 44нКл, находящиеся на расстоянии 8см друг от друга? 2.ВО СКОЛЬКО РАЗ ИЗМЕНИТСЯ ЕМКОСТЬ ПЛОСКОГО КОНДЕНСАТОРА ПРИ УМЕНЬШЕНИИ РАБОЧЕЙ ПЛОЩАДИ ПЛАСТИН В 8РАЗ И УВЕЛИЧЕНИИ РАССТОЯНМЯ МЕЖДУ НИМИ В 4РАЗА?

Answer 1

Вот. Только на счет конечного ответа сомневаюсь. Счет может быть неверный. Но решение правильное. Это первая задача

Answer 2

Interaction between two charges

The force of interaction between two charges can be calculated using Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

1. To find the force of interaction between two charges of 64 nC#### Interaction between two charges The interaction between two charges can be calculated using Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

1. To find the force of interaction between two charges, we can use the formula:

F = k * (q1 * q2) / r^2

Where: - F is the force of interaction between the charges, - k is the electrostatic constant (approximately equal to 9 × 10^9 N m^2/C^2), - q1 and q2 are the magnitudes of the charges (in this case, 64 nC and 44 nC, respectively), - r is the distance between the charges (in this case, 8 cm or 0.08 m).

Plugging in the values, we can calculate the force of interaction between the charges.

F = (9 × 10^9 N m^2/C^2) * ((64 × 10^(-9) C) * (44 × 10^(-9) C)) / (0.08 m)^2

Calculating this expression will give us the answer.

2. To calculate the change in capacitance of a parallel plate capacitor when the working area of the plates is reduced by a factor of 8 and the distance between them is increased by a factor of 4, we can use the formula:

C = (ε₀ * A) / d

Where: - C is the capacitance of the capacitor, - ε₀ is the permittivity of free space (approximately equal to 8.85 × 10^(-12) F/m), - A is the area of the plates, - d is the distance between the plates.

When the working area of the plates is reduced by a factor of 8, the new area becomes 1/8 of the original area. Similarly, when the distance between the plates is increased by a factor of 4, the new distance becomes 4 times the original distance.

Plugging in the values, we can calculate the new capacitance.

C' = (ε₀ * (A/8)) / (4d)

To find the change in capacitance, we can subtract the new capacitance from the original capacitance.

ΔC = C - C'

Calculating this expression will give us the answer.

Please note that the above calculations are based on the given information and assumptions.