Question

Поезд начал тормозить со скоростью 72 км/ч. Какова будет его скорость после прохождения двух третей тормозного пути?

Answer 1

72-(72/3*2)=24
24км час

Answer 2

Calculation of the Train's Speed After Two-Thirds of the Braking Distance

To calculate the train's speed after passing two-thirds of the braking distance, we need to use the given initial speed of 72 km/h and the formula for deceleration.

The formula for deceleration is:

Deceleration = (Final Speed - Initial Speed) / Time

In this case, the initial speed is 72 km/h, and we want to find the final speed after two-thirds of the braking distance. Let's assume the braking distance is represented by 'd'.

The time it takes to cover two-thirds of the braking distance can be calculated as follows:

Time = (2/3) * (Braking Distance / Initial Speed)

Now, let's substitute the values into the formula:

Time = (2/3) * (d / 72)

To find the final speed, we can rearrange the formula for deceleration:

Final Speed = (Deceleration * Time) + Initial Speed

Since the train is decelerating, the deceleration value will be negative. Let's substitute the values into the formula:

Final Speed = (-Deceleration * [(2/3) * (d / 72)]) + 72

Now, let's simplify the equation:

Final Speed = 72 - (Deceleration * (2/3) * (d / 72))

To find the value of the deceleration, we need more information about the train's braking system or the specific conditions of the braking process. Unfortunately, the provided question does not include this information.

Therefore, without the value of the deceleration, we cannot calculate the train's speed after passing two-thirds of the braking distance accurately.

If you have any additional information or specific values for the deceleration, please provide them, and I will be happy to assist you further.