Question

Груз массой 90 кг поднимают равномерно по наклонной плоскости с углом наклона 30 градусов к горизонту прикладывая силу направленную параллельно наклонной плоскости Найдите эту силу если коэффициент трения 3 в корне

Answer 1

Тоже с этим столкнулся, надеюсь все видно

Answer 2

Calculation of the Force Required to Lift a 90 kg Load on an Inclined Plane

To find the force required to lift a 90 kg load on an inclined plane with an angle of inclination of 30 degrees to the horizontal, we need to consider the gravitational force acting on the load and the frictional force opposing its motion.

1. Gravitational Force: The gravitational force acting on the load can be calculated using the formula:

F_gravity = mass × acceleration due to gravity

Given that the mass of the load is 90 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the gravitational force:

F_gravity = 90 kg × 9.8 m/s^2

Calculating this, we find that the gravitational force is approximately 882 N.

2. Frictional Force: The frictional force opposing the motion of the load can be calculated using the formula:

F_friction = coefficient of friction × normal force

The normal force is the component of the gravitational force acting perpendicular to the inclined plane. It can be calculated using the formula:

Normal force = mass × gravitational acceleration × cosine(angle of inclination)

Given that the coefficient of friction is 3√3 (as mentioned in the question), the mass is 90 kg, the gravitational acceleration is 9.8 m/s^2, and the angle of inclination is 30 degrees, we can calculate the normal force and then the frictional force:

Normal force = 90 kg × 9.8 m/s^2 × cos(30 degrees)

F_friction = 3√3 × (90 kg × 9.8 m/s^2 × cos(30 degrees))

Calculating this, we find that the frictional force is approximately 1507.8 N.

3. Force Required to Lift the Load: The force required to lift the load can be calculated by summing the gravitational force and the frictional force:

Force required = F_gravity + F_friction

Force required = 882 N + 1507.8 N

Calculating this, we find that the force required to lift the 90 kg load on the inclined plane is approximately 2389.8 N.

Therefore, the force required to lift the 90 kg load on the inclined plane with an angle of inclination of 30 degrees to the horizontal, while applying a force parallel to the inclined plane, is approximately 2389.8 N.