Question

Средняя кинетическая энергия поступательного движения отдельных молекул газа равна 8*10^21 дж число молекул в 10 см ^3 составляет 5*10^19. определить давление газа

Answer 1

E=8*10^-21 Дж       V=10^-5 м3       N=5*10^19     p=?
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p=(2/3)*n*E=(2/3)(N/V)*E=2*5*10^19*8*10^-21/(3*10^-5)≈27*10^3 Па   (27 кПа)
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Answer 2

Calculating Gas Pressure

To calculate the pressure of a gas using the given information, we can use the ideal gas law, which states:

PV = nRT

Where: - P is the pressure of the gas - V is the volume the gas occupies - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas in Kelvin

We are given the average kinetic energy of the translational motion of individual gas molecules as 8*10^21 J and the number of molecules in 10 cm^3 as 5*10^19.

Calculating the Number of Moles

First, we need to calculate the number of moles of the gas using the given number of molecules.

The number of moles can be calculated using the formula:

n = N / N_A

Where: - n is the number of moles - N is the number of molecules - N_A is Avogadro's number (6.022 x 10^23 mol^-1)

Given: - N = 5*10^19 molecules - N_A = 6.022 x 10^23 mol^-1

Calculating: n = 5*10^19 / 6.022 x 10^23 n ≈ 8.3 x 10^-5 mol

Calculating the Volume

The volume is given as 10 cm^3. We need to convert it to cubic meters for the ideal gas law.

V = 10 cm^3 = 10 x 10^-6 m^3 = 1 x 10^-5 m^3

Calculating the Gas Pressure

Now, we can use the ideal gas law to calculate the pressure of the gas.

Given: - n ≈ 8.3 x 10^-5 mol - V = 1 x 10^-5 m^3 - R is the ideal gas constant (approximately 8.314 J/(mol·K)) - We are not given the temperature (T) in this scenario, so we cannot calculate the pressure without the temperature.

Without the temperature, we cannot calculate the pressure using the ideal gas law. If the temperature is provided, we can proceed with the calculation using the ideal gas law formula.

If you have the temperature of the gas, please provide it, and I can assist you further in calculating the gas pressure.