Question

В проводнике индуктивностью 5 мгн сила тока в течение 0,4 с равномерно возрасиает с 2а до какого то конечного значения при этом в проводнике возникает эдс самоиндукции 0,1в определите конечное значение силы тока

Answer 1

E = - L * dI/dt

dI = -E*dt/L = -0,2 *0.2/0.005 = - 8 А

dI = I1 -I2

I2 = I1 - dI = 2 - (-8) = 10 A

 

ответ 10 А

Answer 2

Calculation of the Final Value of Current

To determine the final value of the current in the conductor, we can use the formula for the rate of change of current in an inductor:

V = L * (di/dt)

Where: - V is the induced electromotive force (emf) or self-induced voltage in the conductor (0.1 V in this case). - L is the inductance of the conductor (5 mH or 0.005 H in this case). - (di/dt) is the rate of change of current with respect to time.

Since the current is increasing uniformly from 2 A to a final value, we can assume a linear relationship between current and time:

I = I0 + (I1 - I0) * (t / T)

Where: - I is the current at any given time. - I0 is the initial current (2 A in this case). - I1 is the final current (the value we want to find). - t is the time elapsed (0.4 s in this case). - T is the total time taken for the current to reach its final value.

To find the final value of the current, we need to solve for I1 in the equation above.

Solution

Let's substitute the given values into the equation and solve for I1:

I = 2 + (I1 - 2) * (0.4 / T)

We also know that the induced emf is equal to the rate of change of current multiplied by the inductance:

0.1 = 0.005 * (di/dt)

Since the current is increasing uniformly, we can assume that the rate of change of current is constant:

di/dt = (I1 - 2) / 0.4

Now we can substitute this expression for di/dt into the equation for the induced emf:

0.1 = 0.005 * (I1 - 2) / 0.4

Simplifying the equation:

0.1 * 0.4 = 0.005 * (I1 - 2)

0.04 = 0.005 * (I1 - 2)

0.04 / 0.005 = I1 - 2

8 = I1 - 2

I1 = 8 + 2

I1 = 10 A

Therefore, the final value of the current in the conductor is 10 A.