Question

С помощью блоков равномерно поднимают груз, масса которого 3 кг, на высоту 0,5 м, действуя силой 40 Н. Вычисли КПД установки. (принять g≈10Н/кг)

Answer 1

КПД=Аполез/Азатр
Аполез=mgh
Aзатр=Fh
КПД=3×10×0,5/40×0,5=30/40=0,75=75%
Ответ 75%

Answer 2

Calculation of Efficiency (КПД) of the System

To calculate the efficiency (КПД) of the system, we need to determine the work input and the work output.

The work input (W_in) is given by the formula:

W_in = Force × Distance

In this case, the force is 40 N and the distance is 0.5 m. Therefore:

W_in = 40 N × 0.5 m = 20 J

The work output (W_out) is given by the formula:

W_out = Mass × Gravity × Height

In this case, the mass is 3 kg, the gravity is approximately 10 N/kg, and the height is 0.5 m. Therefore:

W_out = 3 kg × 10 N/kg × 0.5 m = 15 J

Now, we can calculate the efficiency (КПД) of the system using the formula:

Efficiency (КПД) = (W_out / W_in) × 100%

Substituting the values we calculated:

Efficiency (КПД) = (15 J / 20 J) × 100% = 75%

Therefore, the efficiency (КПД) of the system is 75%.