Question

Лампочка карманного фонаря под напряжением 6 В горит при силе тока 0,5 А. Каково сопротивление спирали лампочки? Дано:??????? пж полностью

Answer 1

R=U/I
I-сила тока
U-напряжение
R-сопротивление
дано:
I=0.5 А
U=6 В
R-?
РЕШЕНИЕ:
R=6/0.5=3Н

Answer 2

Calculation of Resistance

To calculate the resistance of the filament in the pocket flashlight bulb, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). In this case, the voltage is 6 V and the current is 0.5 A.

Using the formula: R = V / I, we can calculate the resistance:

R = 6 V / 0.5 A = 12 Ω

Therefore, the resistance of the filament in the pocket flashlight bulb is 12 ohms.

Please note that the calculation assumes that the filament behaves as a purely resistive element and that the voltage and current values provided are accurate.