Question

Определить массу воды, которую можно нагреть от 2°С до 10°С, затратив 210Дж

Answer 1

Данo
c=4200 Дж/кгград
t1=2 C
t2=10 C
Q=210Дж
m-?
Q=mc(t2-t1)

Answer 2

Calculating the Heat Energy Required to Raise the Temperature of Water

To determine the mass of water that can be heated from 2°C to 10°C while expending 210 J of energy, we can use the formula:

Q = mcΔT

Where: - Q = heat energy (in joules) - m = mass of the substance (in grams) - c = specific heat capacity of the substance (in J/g°C) - ΔT = change in temperature (in °C)

Applying the Formula

Given: - Initial temperature (T1) = 2°C - Final temperature (T2) = 10°C - Heat energy (Q) = 210 J

We can rearrange the formula to solve for the mass (m):

m = Q / (cΔT)

Specific Heat Capacity of Water

The specific heat capacity of water is approximately 4.18 J/g°C.

Calculation

Substitute the given values into the formula:

m = 210 J / (4.18 J/g°C * (10°C - 2°C))

m ≈ 210 J / (4.18 J/g°C * 8°C)

m ≈ 210 J / 33.44 J/g

m ≈ 6.28 g

Answer

The mass of water that can be heated from 2°C to 10°C while expending 210 J of energy is approximately 6.28 grams.