Question

Колесо велосипеда вращается с частотой 2 об/сек. Определите линейную скорость и ускорение точек колеса, если радиус его 0,35 м

Answer 1

Υ=ωR
 ω=2πν=2*3.14*2=12.56
υ=ωR=12.56*0.35=4.39м/c

Answer 2

Calculation of Linear Velocity and Acceleration of a Bicycle Wheel

To determine the linear velocity and acceleration of a bicycle wheel, we need to use the formulae for linear velocity and centripetal acceleration.

The linear velocity of a point on the wheel is given by the formula:

Linear Velocity (v) = 2πr * f

where: - v is the linear velocity, - r is the radius of the wheel, and - f is the frequency of rotation in revolutions per second.

The centripetal acceleration of a point on the wheel is given by the formula:

Centripetal Acceleration (a) = 4π²r * f²

where: - a is the centripetal acceleration, - r is the radius of the wheel, and - f is the frequency of rotation in revolutions per second.

Given that the frequency of rotation is 2 revolutions per second and the radius of the wheel is 0.35 meters, we can calculate the linear velocity and centripetal acceleration.

Calculation:

Using the given values: - Frequency (f) = 2 revolutions per second - Radius (r) = 0.35 meters

We can substitute these values into the formulas to calculate the linear velocity and centripetal acceleration.

Linear Velocity (v) = 2π * 0.35 * 2 = 4.4 m/s Centripetal Acceleration (a) = 4π² * 0.35 * 2² = 17.6 m/s² Therefore, the linear velocity of the points on the bicycle wheel is 4.4 m/s, and the centripetal acceleration is 17.6 m/s².

Please note that the calculations assume that the wheel is rotating at a constant speed and that there is no tangential acceleration.

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