Question

Каков объём сжатого кислорода находящегося в болоне под давлением 6,5кПа при температуре 165 С(градусов цельсия) если масса этого газа 3,8 кг. Малярная масса кислорода равна 0,032 кг/моль.

Answer 1

Уравнение Клапейрона:
pV = (m/M)*R*T
V = ((m/M)*R*T)/p = ((3.8/0.032)*8.3*(165+273))/6500 = 66.4 м^3.

Answer 2

Calculating the Volume of Compressed Oxygen

To calculate the volume of compressed oxygen, we can use the ideal gas law formula:

V = (m * R * T) / (M * P)

Where: - V = volume of the gas - m = mass of the gas - R = ideal gas constant (8.314 J/(mol·K)) - T = temperature in Kelvin - M = molar mass of the gas - P = pressure

Let's calculate the volume using the given values.

Given Values:

- Mass of the gas (m) = 3.8 kg - Molar mass of oxygen (M) = 0.032 kg/mol - Temperature (T) = 165°C - Pressure (P) = 6.5 kPa

First, we need to convert the temperature to Kelvin: T(K) = T(°C) + 273.15

Plugging in the values: T(K) = 165 + 273.15 = 438.15 K

Now, we can calculate the volume using the ideal gas law formula: V = (m * R * T) / (M * P)

Substituting the values: V = (3.8 * 8.314 * 438.15) / (0.032 * 6500)

Let's calculate the result.