Question

В цилиндрический сосуд с площадью основания 10 см^2 налили 1 л воды плотностью р^в=1000 кг/м^3, а поверх воды налили 1 л масла плотность которого р^м=800 кг/м^3. Жидкости не смешиваются. Определить давление на дно сосуда.

Answer 1

V=L*S--->L=V/S=0.001/0.01=0.1 m=10 cm -Уровень до того как ... .m*g=p*g*dV-сила Архимеда dV=m/p=0.1/1000=0.0001 m^3 dL=dV/S=0.0001/0.01=0.01 m =1 sm Уровень воды будет 10+1=11 см.

Answer 2

Calculation of Pressure on the Bottom of the Vessel

To calculate the pressure on the bottom of the cylindrical vessel, we need to consider the weight of the water and the oil in the vessel.

The pressure at a certain depth in a fluid is given by the equation:

P = ρgh

Where: - P is the pressure - ρ is the density of the fluid - g is the acceleration due to gravity - h is the height or depth of the fluid column

In this case, we have two fluids: water and oil. The water has a density of 1000 kg/m^3, and the oil has a density of 800 kg/m^3.

Let's calculate the pressure on the bottom of the vessel for each fluid separately and then add them together.

Calculation for Water:

The volume of water in the vessel is 1 liter, which is equivalent to 0.001 m^3. The density of water is 1000 kg/m^3.

The pressure due to the water can be calculated using the equation:

P_water = ρ_water * g * h_water

Where: - P_water is the pressure due to water - ρ_water is the density of water - g is the acceleration due to gravity - h_water is the height or depth of the water column

Since the vessel is cylindrical, the height of the water column is equal to the volume of water divided by the area of the base of the vessel.

h_water = V_water / A_base

Where: - V_water is the volume of water - A_base is the area of the base of the vessel

The area of the base of the vessel is given as 10 cm^2, which is equivalent to 0.001 m^2.

A_base = 0.001 m^2

Substituting the values into the equation, we can calculate the pressure due to water:

P_water = 1000 kg/m^3 * 9.8 m/s^2 * (0.001 m^3 / 0.001 m^2)

Calculating the above expression gives us the pressure due to water.

Calculation for Oil:

The volume of oil in the vessel is also 1 liter, which is equivalent to 0.001 m^3. The density of oil is 800 kg/m^3.

Using the same equation as before, we can calculate the pressure due to oil:

P_oil = ρ_oil * g * h_oil

Where: - P_oil is the pressure due to oil - ρ_oil is the density of oil - g is the acceleration due to gravity - h_oil is the height or depth of the oil column

Again, since the vessel is cylindrical, the height of the oil column is equal to the volume of oil divided by the area of the base of the vessel.

h_oil = V_oil / A_base

Substituting the values into the equation, we can calculate the pressure due to oil:

P_oil = 800 kg/m^3 * 9.8 m/s^2 * (0.001 m^3 / 0.001 m^2)

Calculating the above expression gives us the pressure due to oil.

Total Pressure on the Bottom of the Vessel:

To find the total pressure on the bottom of the vessel, we add the pressures due to water and oil together:

P_total = P_water + P_oil

Substituting the calculated values for P_water and P_oil, we can find the total pressure on the bottom of the vessel.

Please note that the above calculations assume that the vessel is open to the atmosphere and that the pressure at the surface of the water and oil is atmospheric pressure.

Let's calculate the values and find the total pressure on the bottom of the vessel.