Question

Камень бросили горизонтально с балкона со скоростью 20 м/с. Он упал на землю через 1 с. Найдите высоту балкона и дальность полёта тела

Answer 1

Висота балкону 20 м бо швидкість камня за сикунду сягала понад 20м.с

Answer 2

Calculation of the Balcony Height and Projectile Range

To find the height of the balcony and the range of the projectile, we can use the equations of motion for a horizontally launched projectile.

Let's denote the initial velocity of the projectile as v and the time it takes to reach the ground as t.

The height of the balcony (h) can be calculated using the equation:

h = v * t - (1/2) * g * t^2,

where g is the acceleration due to gravity.

The range of the projectile (R) can be calculated using the equation:

R = v * t.

Given that the initial velocity of the projectile is 20 m/s and it takes 1 second to reach the ground, we can substitute these values into the equations to find the height of the balcony and the range of the projectile.

Using the equation for the height of the balcony:

h = (20 m/s) * (1 s) - (1/2) * (9.8 m/s^2) * (1 s)^2,

we can calculate the height of the balcony.

Using the equation for the range of the projectile:

R = (20 m/s) * (1 s),

we can calculate the range of the projectile.

Let's calculate these values:

h = 20 m - (1/2) * 9.8 m/s^2 * 1 s^2,

R = 20 m/s * 1 s.

Calculating the height of the balcony:

h = 20 m - (1/2) * 9.8 m/s^2 * 1 s^2 = 20 m - 4.9 m = 15.1 m.

Calculating the range of the projectile:

R = 20 m/s * 1 s = 20 m.

Therefore, the height of the balcony is 15.1 meters and the range of the projectile is 20 meters.

Please note that these calculations assume no air resistance and a constant acceleration due to gravity of 9.8 m/s^2.