Question

При торможении перед светофором автомобиль движется прямолинейно и за 5 сек проходит путь 60 м. С каким ускорением двигался автомобиль, если его скорость в начале торможения была равна 20 м\с?

Answer 1

(V^2-V0^2)/2S

Подставляешь и решаешь

Answer 2

Calculation of Acceleration during Braking

To calculate the acceleration of the car during braking, we can use the equation of motion:

\[s = ut + \frac{1}{2}at^2\]

Where: - s is the distance traveled (60 m) - u is the initial velocity (20 m/s) - t is the time taken (5 s) - a is the acceleration (to be determined)

Rearranging the equation, we get:

\[a = \frac{2(s - ut)}{t^2}\]

Substituting the given values:

\[a = \frac{2(60 - 20 \times 5)}{5^2}\]

Simplifying the equation:

\[a = \frac{2(60 - 100)}{25}\]

\[a = \frac{2(-40)}{25}\]

\[a = \frac{-80}{25}\]

\[a = -3.2 \, \text{m/s}^2\]

Therefore, the car was decelerating with an acceleration of -3.2 m/s^2 during braking.

Please note that the negative sign indicates deceleration or slowing down.