Question

Латунный цилиндр массой 150 г нагрели в кипящей воде и опустили в сосуд с водой. Вода в сосуде нагрелась до 40С. Какое количество теплоты отдал цилиндр воде при охлаждении? Нагреванием воздуха и сосуда принебречь.

Answer 1

 

формула: Q=cm(t2-t1)  у тебя дано: m=150г(0,15кг) t1=100(т.к температура кипения) t2=40.

  c - теплоёмкость латуни = 380 Дж/кг*градусы.подставляешь значения в формулу Q=380*0,15*(40-100). если у тебя есть ответ.но он не сошелся, попробуй не 40-100, а 100-40.

Answer 2

Calculation of Heat Transfer

To calculate the amount of heat transferred from the brass cylinder to the water during cooling, we can use the equation:

Q = mcΔT

Where: - Q is the amount of heat transferred (in joules) - m is the mass of the brass cylinder (in kilograms) - c is the specific heat capacity of brass (in joules per kilogram per degree Celsius) - ΔT is the change in temperature of the water (in degrees Celsius)

Given: - Mass of the brass cylinder (m) = 150 grams = 0.15 kilograms - Change in temperature of the water (ΔT) = 40°C (final temperature) - initial temperature (assumed to be the same as the boiling water) = 40°C - 100°C = -60°C

Now, we need to find the specific heat capacity of brass (c). Unfortunately, the search results provided do not contain the specific heat capacity of brass. However, we can assume that the specific heat capacity of brass is similar to that of copper, which is approximately 385 J/kg°C.

Using the equation, we can calculate the amount of heat transferred:

Q = (0.15 kg) * (385 J/kg°C) * (-60°C)

Calculating this, we find that the amount of heat transferred from the brass cylinder to the water during cooling is approximately -3,465 joules.

Please note that the negative sign indicates that heat is being transferred from the brass cylinder to the water, resulting in a decrease in temperature for the brass cylinder and an increase in temperature for the water.