Question

Мальчик бросил горизонтально мяч из окна, находящегося на высоте 20м. Определите, с какой скоростью был брошен мяч , если он упал на расстоянии 6м от основания дома.

Answer 1

X(t)=v0*t
y(t)=y0-g*t^2/2
x(t1)=6м, y(t1)=0, y0=20м, g=10 м/с2
t1 – время падения мяча.
Теперь всё подставляем:
t1=6/v0
20=g*t^2/2
.........
v0=3м/с
t1=2 c

Answer 2

Calculation of the Initial Velocity of the Ball

To determine the initial velocity with which the ball was thrown horizontally out of the window, we can use the equation of motion for horizontal projectile motion. In this case, the vertical component of the initial velocity is zero since the ball was thrown horizontally.

The equation for the horizontal distance traveled by a projectile is given by:

d = v * t

where: - d is the horizontal distance traveled by the projectile (6m in this case) - v is the initial velocity of the projectile - t is the time of flight

To solve for the initial velocity, we need to find the time of flight. We can use the equation for vertical motion to find the time it takes for the ball to fall from a height of 20m:

h = (1/2) * g * t^2

where