Question

8.Азот массой 7 г находится под давлением 0,1 мПа и температуре 290 К. Вследствие изобарного нагревания газ занял объём 10 л. Определить объём газа до расширения, температуру после расширения, плотность до и после расширения.

Answer 1

Решение в прикрепленном файле!

Answer 2

Calculation of Gas Volume Before Expansion

To determine the volume of the gas before expansion, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (0.1 mPa) - V is the volume of the gas before expansion (unknown) - n is the number of moles of the gas (unknown) - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (290 K)

We can rearrange the equation to solve for V:

V = (nRT) / P

To find the number of moles (n), we can use the formula:

n = m / M

Where: - m is the mass of the gas (7 g) - M is the molar mass of nitrogen (28 g/mol)

Substituting the values into the equation, we get:

n = 7 g / 28 g/mol = 0.25 mol

Now we can calculate the volume (V) using the ideal gas law equation:

V = (0.25 mol * 8.314 J/(mol·K) * 290 K) / (0.1 mPa)

Let's calculate the value of V.