Question

При торможении автомобиль движется с ускорением 5 м\с2.На каком минимальном расстоянии от препятствия водитель должен начать торможение,если скорость автомобиля 20 м\с? помогите пожалуйста(

Answer 1

Дано: Vo=20, a=5, V=0

Найти: S-?

Решение: 1) S=(V^2-Vo^2)/2a= -400/-10=40 м

Ответ: 40 м

Answer 2

Calculation of Minimum Braking Distance

To calculate the minimum braking distance, we need to use the equation of motion:

v^2 = u^2 + 2as

Where: - v is the final velocity (0 m/s, as the car comes to a stop) - u is the initial velocity (20 m/s, the speed of the car) - a is the acceleration (in this case, the deceleration due to braking, which is -5 m/s^2) - s is the distance traveled during braking (what we want to find)

Rearranging the equation, we have:

s = (v^2 - u^2) / (2a)

Substituting the given values:

s = (0^2 - 20^2) / (2 * -5) = 400 / -10 = -40 m

The negative sign indicates that the distance is in the opposite direction of the car's motion. However, distance cannot be negative, so we take the absolute value:

|s| = 40 m

Therefore, the minimum distance from the obstacle at which the driver should start braking is 40 meters.