Question

Пружина удлинилась на 20 см под действием силы 20 Н. какова ее жесткость?

Answer 1

K=20 Н \0,2м
ответ 200 ньютон/метр

Answer 2

Calculation of the Spring Constant

To determine the spring constant (also known as the stiffness or force constant) of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = kx

Where: - F is the force applied to the spring, - k is the spring constant, and - x is the displacement of the spring from its equilibrium position.

In this case, the spring elongated by 20 cm (or 0.2 m) under the action of a force of 20 N. We can use this information to calculate the spring constant.

Using Hooke's Law, we can rearrange the equation to solve for the spring constant:

k = F / x

Substituting the given values:

k = 20 N / 0.2 m

Calculating the result:

k = 100 N/m

Therefore, the spring constant of the spring is 100 N/m.