Question

На плоскопаралельную пластинку толщиной 10 см падает луч света под углом 40 градусов. Проходя через пластинку, он смещается на 3 см. Найти показатель преломления вещества пластинки Пожалуйста решите очень надо

Answer 1

 n=sin(40)/sin(б), где sim(б)=3/sqr(109) (скр - квадратный корень)

Answer 2

Calculating the refractive index of the material

We are given the following information: - A light ray falls on a parallel plate of thickness 10 cm at an angle of 40 degrees. - After passing through the plate, the ray is displaced by 3 cm.

To calculate the refractive index of the material, we can use Snell's law. Snell's law relates the angle of incidence, angle of refraction, and the refractive indices of the two media as:

`n1 * sin(θ1) = n2 * sin(θ2)`

Where: - `n1` is the refractive index of the first medium - `n2` is the refractive index of the second medium - `θ1` is the angle of incidence - `θ2` is the angle of refraction

In this case, the first medium is air (with a refractive index of approximately 1) and the second medium is the material of the parallel plate.

We know: - `θ1 = 40°` (given) - Displacement of ray = 3 cm - Thickness of plate = 10 cm

Using trigonometry, we can relate the displacement to the angle of refraction `θ2` inside the material:

`tan(θ2) = Displacement / Thickness` `tan(θ2) = 3 cm / 10 cm` `θ2 = tan^-1(0.3) = 16.7°`

Now using Snell's law: `n1 * sin(40°) = n2 * sin(16.7°)` `1 * sin(40°) = n2 * sin(16.7°)` `n2 = 1 / sin(16.7°) = 1.5`

Therefore, the refractive index of the material of the parallel plate is 1.5.