Question

При остывании медной детали массой 300 г выделилось 11,7 кДж теплоты. На сколько градусов Цельсия уменьшилась при этом температура детали? Удельная теплоёмкость меди 390 Дж/(кгК).

Answer 1

Q=mct
t=Q/mc=11700/(0,3*390)=100
Изменилось на 100°С

Answer 2

Calculation of Temperature Change

To calculate the change in temperature of the copper part, we can use the formula:

Q = mcΔT

Where: - Q is the heat energy released (11.7 kJ) - m is the mass of the copper part (300 g = 0.3 kg) - c is the specific heat capacity of copper (390 J/(kg·K)) - ΔT is the change in temperature we want to find

Rearranging the formula, we can solve for ΔT:

ΔT = Q / (mc)

Substituting the given values:

ΔT = 11.7 kJ / (0.3 kg × 390 J/(kg·K))

Calculating the result:

ΔT ≈ 100°C

Therefore, the temperature of the copper part decreased by approximately 100 degrees Celsius during the cooling process.