Question

в сосуде смешали воду при температуре 10°С и воду при температуре 90°С. через некоторое время в сосуде установилась температура 40°С. . рассчитайтеотношение массы холодной воды к массе горячей С дано,пожалуйста не берите решения с других сайтов,я там уже смотрела

Answer 1

Я и не беру!
Холодная вода нагревается:
Q1 = c*m1*(t-t1) 

Горячая вода остывает:
Q2 = c*m2*(t2-t)

 По закону сохранения энергии:
Q1=Q2

c*m1*(40-10)=c*m2*(90-40)
30*m1=50*m2
m1 / m2 = 50/30

Или:
m1 : m2 = 5 : 3

Всё!

Answer 2

Calculation of the Ratio of Masses of Cold and Hot Water

To calculate the ratio of the mass of cold water to the mass of hot water, we can use the principle of heat transfer. The heat gained by the cold water is equal to the heat lost by the hot water. This can be expressed using the formula:

m1 * c1 * (Tf - T1) = m2 * c2 * (T2 - Tf)

Where: - m1 is the mass of cold water - c1 is the specific heat capacity of water (approximately 4.18 J/g°C) - Tf is the final temperature (40°C) - T1 is the initial temperature of the cold water (10°C) - m2 is the mass of hot water - c2 is the specific heat capacity of water (approximately 4.18 J/g°C) - T2 is the initial temperature of the hot water (90°C)

We can rearrange the equation to solve for the ratio of the masses:

m1/m2 = (c2 * (T2 - Tf)) / (c1 * (Tf - T1))

Substituting the given values into the equation:

m1/m2 = (4.18 * (90 - 40)) / (4.18 * (40 - 10))

Simplifying the equation:

m1/m2 = 50 / 104

Therefore, the ratio of the mass of cold water to the mass of hot water is 50:104.