Question

Найти среднюю квадратичную скорость молекулы водорода при температуре 27°С

Answer 1

Д ано T=300 K    m=2*1,66*10^-27 кг    V-?
V= корень из 3*k*T/mo=  корень3*1,38*10^-23*300/2*1,66*10^-27=2,03 км/с

Answer 2

Finding the Average Square Velocity of Hydrogen Molecules at 27°C

To find the average square velocity of hydrogen molecules at a temperature of 27°C, we can use the formula:

v = sqrt((3kT) / m)

Where: - v is the average square velocity of the molecules - k is the Boltzmann constant (1.38 x 10^-23 J/K) - T is the temperature in Kelvin - m is the molar mass of the gas in kg/mol

To convert the temperature from Celsius to Kelvin, we add 273.15 to the Celsius temperature.

Let's calculate the average square velocity of hydrogen molecules at 27°C using the given formula.

Calculation:

1. Convert the temperature from Celsius to Kelvin: - 27°C + 273.15 = 300.15 K

2. Determine the molar mass of hydrogen (H2): - The molar mass of hydrogen (H2) is approximately 2 g/mol or 0.002 kg/mol.

3. Substitute the values into the formula: - v = sqrt((3 * 1.38 x 10^-23 J/K * 300.15 K) / 0.002 kg/mol)

4. Calculate the average square velocity: - v ≈ 1937.7 m/s

Therefore, the average square velocity of hydrogen molecules at a temperature of 27°C is approximately 1937.7 m/s.

Please note that this calculation assumes ideal gas behavior and uses the molar mass of hydrogen (H2).