Question

С какой силой магнитное поле действует на частицу с электрическим зарядом 1,6*10-19 Кл. если она движется в однородном магнитном поле с индукцией 2 Тл со скоростью 100000 км/с

Answer 1

22222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222$\sqrt[n]{x}$

Answer 2

Calculating the Force of a Magnetic Field on a Moving Charged Particle

To calculate the force of a magnetic field on a moving charged particle, we can use the formula:

F = qvBsin(θ)

Where: - F is the force in Newtons - q is the charge of the particle in Coulombs - v is the velocity of the particle in m/s - B is the magnetic field strength in Tesla - θ is the angle between the velocity vector and the magnetic field vector

Given: - q = 1.6*10^-19 C - v = 100000 km/s = 100000000 m/s - B = 2 T - The angle between the velocity vector and the magnetic field vector is not provided, so we assume it to be 90 degrees for simplicity.

Using the given values, we can calculate the force of the magnetic field on the charged particle.

Calculation

Using the formula F = qvBsin(θ), and assuming θ = 90 degrees: ``` F = (1.6*10^-19 C) * (100000000 m/s) * (2 T) * sin(90°) ``` ``` F = 3.2*10^-11 N ```

Conclusion

The force of the magnetic field on the charged particle is 3.2*10^-11 N. This force is acting perpendicular to the velocity of the charged particle.