Question

Каток работающий на укладке шоссе, оказывает на него давление 400 кПа. Площадь опоры катка 0,12м2. Чему равна масса этого катка0,12м2-это 0,12м во второй степени

Answer 1

400кПа=400000Паp=F/SF=pSF= 400кПа*0,12м^2=400000Па*0,12м^2=48000Н=48кН

Answer 2

Calculation of the Mass of the Roller

To calculate the mass of the roller, we can use the formula:

m = P * S / g

Where: - m is the mass of the roller - P is the pressure exerted on the roller (400 kPa) - S is the area of contact between the roller and the road (0.12 m^2) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values into the formula, we can calculate the mass of the roller:

m = 400,000 Pa * 0.12 m^2 / 9.8 m/s^2

Using the given values, the mass of the roller is approximately 4,897 kg.

Therefore, the mass of the roller is approximately 4,897 kg