Question

ПОМОГИ ПОЖАЛУЙСТА!!!!1. Вода освещена красным светом. Какой будет длина волны для этого света в воде, если в воздухе она равна 0,75 мкм? Показатель преломления воды равен 1,33. Какой цвет увидит человек, открывающий глаза под водой?2. Могут ли интерферировать световые волны, идущие от двух электрических лампочек?3. На поверхности компакт-дисков видны цветовые полосы. Как объяснить это явление?4. На дифракционную решётку с периодом 0,02 мм падает монохроматическая волна.Какова длина волны применённого излучения, если дифракционный максимум первого порядка расположен на расстоянии 3,6 см от максимума нулевого порядка. Расстояние между экраном и дифракционной решёткой равно 1,8 м.5. Два когерентных источника, расстояние между которыми равно 0,5 мм, испускает монохроматический свет с длиной волны 600 нм. Определите расстояние от первого максимума интерференционной картины до точки экрана, равноудалённой от источников. Расстояние от источников до экрана равно 3 м.

Answer 1

2. Могут. Интерфирировать могут все волны, однако устойчивая интерференционная картина будет наблюдаться только в том случае, если волны имеют одинаковую частоту и колебания в них не ортогональны. 
3. Свет разлагается в спектр, так как каждая составляющая белого света (которая имеет свою собственную длину волны) по разному отражается и преломляется.

Остальные ответы и решения во вложении

Answer 2

Calculating Wavelength of Light in Water

To calculate the wavelength of light in water, we can use the formula:

λ = λ₀ / n

Where: - λ = wavelength of light in water - λ₀ = wavelength of light in air - n = refractive index of water

Given: - Wavelength of light in air, λ₀ = 0.75 µm - Refractive index of water, n = 1.33

Using the given values, we can calculate the wavelength of light in water:

λ = 0.75 µm / 1.33

λ ≈ 0.5647 µm

Therefore, the wavelength of the red light in water would be approximately 0.5647 µm.

Color Perception Underwater

When a person opens their eyes underwater, the colors they see are altered due to the absorption and scattering of light. The longer wavelengths (reds and oranges) are absorbed more quickly, leaving the shorter wavelengths (blues and greens) dominant. As a result, the person would perceive the surroundings as predominantly blue-green.

Interference of Light Waves from Two Electric Bulbs

Yes, light waves from two electric bulbs can interfere with each other. When two coherent sources of light (such as electric bulbs) are close enough, they can produce an interference pattern. This occurs due to the superposition of the waves, leading to areas of constructive and destructive interference.

Explanation for the Visible Color Bands on Compact Discs

The visible color bands on compact discs are a result of diffraction. When light strikes the closely spaced tracks on the surface of a compact disc, it undergoes diffraction, causing interference patterns that result in the observed color bands. This phenomenon is due to the interaction of light waves with the microscopic grooves on the disc's surface.

Calculating Wavelength of Incident Radiation on a Diffraction Grating

To calculate the wavelength of the incident radiation on a diffraction grating, we can use the formula:

d * sin(θ) = m * λ

Where: - d = period of the grating - θ = angle of diffraction - m = order of the maximum - λ = wavelength of the incident radiation

Given: - Period of the grating, d = 0.02 mm - Distance between the screen and the diffraction grating, L = 1.8 m - Distance of the first order maximum from the zero order maximum, x = 3.6 cm = 0.036 m

Using the given values, we can calculate the wavelength of the incident radiation:

λ = (d * x) / (L * m)

Substitute the values: λ = (0.02 mm * 0.036 m) / (1.8 m * 1)

λ = 0.00036 mm / 1.8

λ ≈ 0.0002 mm

Therefore, the wavelength of the incident radiation is approximately 0.0002 mm.

Interference Pattern Distance Calculation

To determine the distance from the first maximum of the interference pattern to a point on the screen equidistant from the sources, we can use the formula for the path difference:

Δx = m * λ * L / d

Where: - Δx = distance from the central maximum to the m-th maximum - m = order of the maximum - λ = wavelength of the light - L = distance from the sources to the screen - d = distance between the sources

Given: - Wavelength of the light, λ = 600 nm - Distance between the sources, d = 0.5 mm - Distance from the sources to the screen, L = 3 m

Using the given values, we can calculate the distance from the first maximum to the point on the screen:

Δx = (1 * 600 nm * 3 m) / 0.5 mm

Δx = (1.8 * 10^-6 m * 3 m) / 0.5 * 10^-3 m

Δx = 10.8 * 10^-6 m / 0.5 * 10^-3 m

Δx ≈ 21.6 mm

Therefore, the distance from the first maximum of the interference pattern to a point on the screen equidistant from the sources is approximately 21.6 mm.