Question

Кинетическая энергия тела в момент броска равна 200 дж . определите до какой высоты от поверхности земли может подняться тело если его масса равна 500 г

Answer 1

Вся кинетическая энергия перейдёт в потенциальную на максимальной высоте. Ep = mgh. Отсюда найдём h = Ep\mg. Ep равна кинетической. h = 200\ 0,5*9,8 = 40,8 м.

Answer 2

Calculation of the Maximum Height

To determine the maximum height to which the object can rise, we can use the principle of conservation of mechanical energy. The initial kinetic energy of the object at the moment of throwing is given as 200 J. The mass of the object is 500 g, which is equal to 0.5 kg.

According to the principle of conservation of mechanical energy, the initial kinetic energy is equal to the sum of the potential energy at the maximum height and the final kinetic energy at that height.

Let's denote the maximum height as h.

Using the formula for kinetic energy (KE) and potential energy (PE), we can write the equation as follows:

KE_initial = PE_max_height + KE_final

Substituting the given values:

200 J = m * g * h + 0 J

Where: - m is the mass of the object (0.5 kg) - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the maximum height

Simplifying the equation:

200 J = 0.5 kg * 9.8 m/s^2 * h

Now we can solve for h:

h = 200 J / (0.5 kg * 9.8 m/s^2)

Calculating the value:

h ≈ 40.82 meters

Therefore, the object can rise to a maximum height of approximately 40.82 meters above the surface of the Earth.