Question

На проводник массой 10 г и длиной 5 см, помещенный в магнитное поле перпендикулярно линиям магнитной индукции, действует со стороны магнитного поля сила. Сила тока в проводнике 8 ампер. Определите модуль вектора магнитной индукции, если проводник находится в равновесии

Answer 1

M=10г=0,01 кг; L= 5см=0,05м
решение:
Fтяж.=F  
Fтяж.=mg     
=> F = 0.01* 10 = 0.1Н     
B= F/IL= 0.1 / 8*0.05 = 0.25 Тл.

Answer 2

Calculation of the Magnetic Field Strength

To determine the magnetic field strength, we can use the formula:

F = BIL

Where: - F is the force acting on the conductor - B is the magnetic field strength - I is the current flowing through the conductor - L is the length of the conductor

In this case, the force acting on the conductor is equal to zero since the conductor is in equilibrium. Therefore, we can set the equation to:

0 = BIL

Given that the mass of the conductor is 10 g and the length is 5 cm, we can convert these values to SI units:

- Mass: 10 g = 0.01 kg - Length: 5 cm = 0.05 m

The current flowing through the conductor is given as 8 A.

Substituting the values into the equation, we have:

0 = B * 0.01 kg * 0.05 m * 8 A

Simplifying the equation, we find:

0 = 0.004B

Therefore, the magnetic field strength (B) must be equal to zero for the conductor to be in equilibrium.

Please note that the information provided does not specify the units for the magnetic field strength. If you have any additional information or specific units, please let me know so I can provide a more accurate answer.