Question

Летчик давит на сиденье кресла самолёта в нижней точке петли Нестерова с силой 4800 Н. Масса летчика равна 80кг. Радиус петли равен 800 м. Чему равна линейная скорость движения самолёта в м/с???

Answer 1

По III З.Н
Fд = N
По II З.Н
ma = N + mg 
mV^2/R = N+mg
oy: mV^2/R = N-mg
V^2 = R(N-mg)/m
V = $\sqrt{ \frac{R(N-mg)}{m} } = \sqrt{ \frac{800(4800-800)}{80} } = 200$ м/с

Answer 2

Calculation of Linear Speed of the Aircraft

To calculate the linear speed of the aircraft at the bottom of Nesterov's loop, we can use the following formula:

Linear speed (v) = √(g * r)

Where: - g = acceleration due to gravity (approximately 9.81 m/s²) - r = radius of the loop

Given: - Force applied by the pilot = 4800 N - Pilot's mass = 80 kg - Radius of the loop = 800 m

First, we need to calculate the acceleration due to the force applied by the pilot.

Calculation of Acceleration

The acceleration can be calculated using the formula:

Acceleration (a) = Force (F) / Mass (m)

Where: - F = force applied by the pilot - m = mass of the pilot

Using the given values: Acceleration (a) = 4800 N / 80 kg = 60 m/s²

Calculation of Linear Speed

Now, we can calculate the linear speed of the aircraft at the bottom of the loop using the formula mentioned earlier:

Linear speed (v) = √(g * r) Linear speed (v) = √(9.81 m/s² * 800 m) Linear speed (v) ≈ 88.63 m/s

Therefore, the linear speed of the aircraft at the bottom of Nesterov's loop is approximately 88.63 m/s.