Question

Луч света падает на поверхность воды под углом 30 градусов. найти угол преломления луча, если абсолютный показатель преломления для воды равен 1,33

Answer 1

По закону Снелиуса:
1sinα = nsinφ (α - угол падения; φ - угол преломления; n - показатель преломления воды; 1 - показатель преломления воздуха)

n = 1.33 = 4/3

В числах: 1/2 = 4/3sinφ

sinφ = 1/2×3/4
sinφ = 3/8

φ = arcsin(3/8) ≈ 22.02°

Answer 2

Calculation of the Angle of Refraction

To find the angle of refraction, we can use Snell's law, which relates the angles of incidence and refraction to the refractive indices of the two media involved. Snell's law is given by the equation:

n1 * sin(θ1) = n2 * sin(θ2)

Where: - n1 is the refractive index of the medium the light is coming from (in this case, air) - θ1 is the angle of incidence - n2 is the refractive index of the medium the light is entering (in this case, water) - θ2 is the angle of refraction

In this case, the light is coming from air (where the refractive index is approximately 1) and entering water (where the refractive index is 1.33). The angle of incidence is given as 30 degrees.

Let's calculate the angle of refraction using Snell's law:

n1 * sin(θ1) = n2 * sin(θ2)

Substituting the given values: 1 * sin(30) = 1.33 * sin(θ2)

Simplifying the equation: sin(30) = 1.33 * sin(θ2)

To find the value of sin(θ2), we can rearrange the equation: sin(θ2) = sin(30) / 1.33

Now, we can calculate the value of sin(θ2) using a scientific calculator or online tool: sin(θ2) ≈ 0.448

To find the angle θ2, we can take the inverse sine (arcsine) of the value: θ2 ≈ arcsin(0.448)

Using a scientific calculator or online tool, we find that: θ2 ≈ 27.3 degrees

Therefore, the angle of refraction is approximately 27.3 degrees