Question

Кусок льда массой 5 кг имеет температуру -10 градусов. Какое количество теплоты необходимо ему передать, чтобы превратить лед в воду?

Answer 1

Лед нагревается= Cльдаmльда(t2-t1)
лед плавится=ㅅ(наклон влево - лямбда)mльда
Q=Cm (t2-t1)+ㅅm
Q=2100×5×10+330000×5=105000+1650000=1755000дж

Answer 2

Calculation of Heat Required to Convert Ice to Water

To calculate the amount of heat required to convert ice to water, we can use the equation:

Q = m * L

Where: - Q is the amount of heat required (in joules) - m is the mass of the ice (in kilograms) - L is the specific latent heat of fusion for ice (in joules per kilogram)

Given that the mass of the ice is 5 kg and the temperature is -10 degrees Celsius, we can find the specific latent heat of fusion for ice and calculate the amount of heat required.

Specific Latent Heat of Fusion for Ice

The specific latent heat of fusion for ice is the amount of heat required to convert 1 kilogram of ice at its melting point to 1 kilogram of water at the same temperature. It is equal to 2,300,000 joules per kilogram.

Calculation

Using the equation Q = m * L, we can substitute the values:

Q = 5 kg * 2,300,000 J/kg

Calculating the result:

Q = 11,500,000 joules

Therefore, 11,500,000 joules of heat are required to convert 5 kg of ice at -10 degrees Celsius to water.

Please note that this calculation assumes that the ice is at its melting point and does not take into account any additional heat required to raise the temperature of the water above its melting point.

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