Question

Мяч,брошенный вертикально вверх,упал в исходную точку через 3,0с.С какой начальной скоростью был брошен мяч?

Answer 1

ну эт для 1-го класса))

время подъема будет равно времени падения, значит он поднимался равнозамедленно 1,5 сек с отрицательным ускорением g=9,8 м/с², в высшей точке подъема его скорость стала=0

отсюда нач. скорость=9,8*1,5=14,7 м/с

 

 

Answer 2

Calculation of Initial Velocity of the Ball

To determine the initial velocity of the ball, we can use the equation of motion for an object in free fall. When a ball is thrown vertically upwards and then falls back down, the total time taken for the ball to return to its initial position is equal to twice the time taken to reach the maximum height.

Given that the ball falls back to its initial position after 3.0 seconds, we can conclude that it takes 1.5 seconds for the ball to reach its maximum height. Using this information, we can calculate the initial velocity of the ball.

The equation for the time taken to reach the maximum height is:

t = V0 / g where: - t is the time taken to reach the maximum height (1.5 seconds) - V0 is the initial velocity of the ball - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Rearranging the equation to solve for V0, we have:

V0 = t * g Substituting the given values, we get:

V0 = 1.5 s * 9.8 m/s^2 = 14.7 m/s

Therefore, the initial velocity of the ball when it was thrown vertically upwards was 14.7 m/s.