
Брусок, начиная равноускренное движение по наклонной плоскости за первую секунду прошел 5 м. Какой
путь пройдет он за первые 5 секунд? За четвертую секунду? С каким ускорением движется брусок? Решать с Дано Найти Решение, другие ответы блокирую!!!!!!!!!!!!!!

Ответы на вопрос

t=1c
S=5м
Найти:S1(t=4c),a,S2(t=5c)
Решение:
S=
a=10 м/с^2
S1=160/2=80м
S2=250/2=125м
Ответ:a=10м/с^2 , S1=80 м , S2= 125м



Given:
- Initial velocity of the block, u = 0 m/s (since it starts from rest) - Distance covered in the first second, s = 5 mTo Find:
1. The total distance covered by the block in the first 5 seconds. 2. The distance covered by the block in the fourth second. 3. The acceleration of the block.Solution:
1. To find the total distance covered by the block in the first 5 seconds, we can use the equation of motion:s = ut + (1/2)at^2
Here, s is the distance covered, u is the initial velocity, t is the time, and a is the acceleration.
Since the block starts from rest, the initial velocity u is 0 m/s. Therefore, the equation simplifies to:
s = (1/2)at^2
Plugging in the values, we have:
5 = (1/2)a(1)^2
Solving for a, we get:
a = 10 m/s^2
Now, we can find the total distance covered in the first 5 seconds using the same equation:
s = ut + (1/2)at^2
Plugging in the values, we have:
s = 0(5) + (1/2)(10)(5)^2
Simplifying, we get:
s = 125 m
Therefore, the block will cover a total distance of 125 meters in the first 5 seconds.
2. To find the distance covered by the block in the fourth second, we can use the equation of motion:
s = ut + (1/2)at^2
Plugging in the values, we have:
s = 0(4) + (1/2)(10)(4)^2
Simplifying, we get:
s = 80 m
Therefore, the block will cover a distance of 80 meters in the fourth second.
3. The acceleration of the block is given by a = 10 m/s^2.
Therefore, the block is moving with an acceleration of 10 m/s^2.
Answer:
1. The block will cover a total distance of 125 meters in the first 5 seconds. 2. The block will cover a distance of 80 meters in the fourth second. 3. The block is moving with an acceleration of 10 m/s^2.

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