Question

Два заряда находящиеся на расстоянии 3 см взаимодействуют в диэлектрике с силой 60 мкН. Определить диэлектрическую проницаемость диэлектрика, если величины зарядов 3 и 5 нКл

Answer 1

F=k*q1*q2/e*R^2
e=k*q1*q2/F*R^2=9*10^9*3*10^-9*5*10^-9/60*10^-6*9*10^-4=2,5

Answer 2

Calculation of the Electric Force between Two Charges in a Dielectric

To determine the dielectric constant of a dielectric material, we can use the formula for the electric force between two charges in a dielectric medium. The formula is given by:

F = (1 / (4πε₀εᵣ)) * (q₁q₂ / r²)

Where: - F is the electric force between the charges, - ε₀ is the vacuum permittivity (8.854 x 10⁻¹² C²/Nm²), - εᵣ is the relative permittivity or dielectric constant of the material, - q₁ and q₂ are the magnitudes of the charges, and - r is the distance between the charges.

In this case, we have two charges with magnitudes of 3 nC and 5 nC, respectively, and they are separated by a distance of 3 cm (0.03 m). The electric force between them is given as 60 μN (60 x 10⁻⁶ N).

To find the dielectric constant (εᵣ), we can rearrange the formula as follows:

εᵣ = (1 / (4πε₀)) * (q₁q₂ / (Fr²))

Let's substitute the given values into the formula and calculate the dielectric constant.

Calculation:

Given: - q₁ = 3 nC (3 x 10⁻⁹ C) - q₂ = 5 nC (5 x 10⁻⁹ C) - r = 3 cm (0.03 m) - F = 60 μN (60 x 10⁻⁶ N)

Using the formula:

εᵣ = (1 / (4πε₀)) * (q₁q₂ / (Fr²))

Substituting the values:

εᵣ = (1 / (4π(8.854 x 10⁻¹² C²/Nm²))) * ((3 x 10⁻⁹ C)(5 x 10⁻⁹ C) / ((60 x 10⁻⁶ N)(0.03 m)²))

Calculating the result:

εᵣ ≈ 25.3

Therefore, the dielectric constant of the dielectric material is approximately 25.3.

Please note that the calculation provided is based on the given information and assumes ideal conditions. The actual value may vary depending on the specific properties of the dielectric material used.