Question

3)Два мальчика на роликовых коньках, оттолкнувшись друг от друга, поехали в разные стороны скоростью 10 м/с и и 6 м/с соответственно. Масса первого мальчика 50 кг. Чему равна масса второго мальчика? со 4)Мальчик массой 60 кг прыгнул на берег со скоростью 1,2 м/с с неподвижного плота массой 0,7 т. Какую скорость приобрел плот?​

Answer 1

Ответ:

щяс напишу

Объяснение:

Answer 2

Answer 3:

Два мальчика на роликовых коньках, оттолкнувшись друг от друга, поехали в разные стороны со скоростью 10 м/с и 6 м/с соответственно. Масса первого мальчика составляет 50 кг. Чему равна масса второго мальчика?

To find the mass of the second boy, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Therefore, we can write the equation:

(mass of the first boy * velocity of the first boy) + (mass of the second boy * velocity of the second boy) = 0

Substituting the given values: (50 kg * 10 m/s) + (mass of the second boy * 6 m/s) = 0

Simplifying the equation: 500 kg*m/s + 6 * (mass of the second boy) = 0

Solving for the mass of the second boy: 6 * (mass of the second boy) = -500 kg*m/s (mass of the second boy) = -500 kg*m/s / 6

Therefore, the mass of the second boy is approximately -83.33 kg. However, it is important to note that mass cannot be negative, so this result is not physically meaningful. It is possible that there is an error in the given information or calculation.

Answer 4:

Мальчик массой 60 кг прыгнул на берег со скоростью 1,2 м/с с неподвижного плота массой 0,7 т. Какую скорость приобрел плот?

To find the velocity acquired by the raft, we can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

The momentum of an object is given by the product of its mass and velocity. Therefore, we can write the equation:

(mass of the boy * velocity of the boy) + (mass of the raft * velocity of the raft before the jump) = (mass of the boy * velocity of the boy after the jump) + (mass of the raft * velocity of the raft after the jump)

Substituting the given values: (60 kg * 1.2 m/s) + (0.7 t * 0 m/s) = (60 kg * 0 m/s) + (0.7 t * velocity of the raft after the jump)

Simplifying the equation: 72 kg*m/s + 0 kg*m/s = 0 kg*m/s + 0.7 t * velocity of the raft after the jump

Since the velocity of the raft before the jump is 0 m/s, the equation becomes: 72 kg*m/s = 0.7 t * velocity of the raft after the jump

Solving for the velocity of the raft after the jump: velocity of the raft after the jump = 72 kg*m/s / (0.7 t)

Converting the mass of the raft from tons to kilograms: mass of the raft = 0.7 t * 1000 kg/t = 700 kg

Substituting the values: velocity of the raft after the jump = 72 kg*m/s / (700 kg)

Therefore, the velocity acquired by the raft is approximately 0.103 m/s.