Question

між двома пристанями за течією річки Катер проходить відстань 300 км за 10 год, а проти течії - за 15 год. Обчисли власну швидкість катера в стоя- чій воді.​

Answer 1

Ответ:

v(проти течії)=300/15=20км/год

v(за течією)=300/10=30км/год

v(катера)=(20+30)2=25км/год

v(течії)=30-25=5км/год

Answer 2

Calculation of the Boat's Speed in Still Water

To calculate the boat's speed in still water, we can use the formula:

Speed in still water = (Speed downstream + Speed upstream) / 2

Given that the boat travels a distance of 300 km downstream in 10 hours and the same distance upstream in 15 hours, we can substitute these values into the formula to find the boat's speed in still water.

Let's calculate it step by step:

1. Speed downstream: - Distance = 300 km - Time = 10 hours - Speed downstream = Distance / Time = 300 km / 10 hours = 30 km/h

2. Speed upstream: - Distance = 300 km - Time = 15 hours - Speed upstream = Distance / Time = 300 km / 15 hours = 20 km/h

3. Speed in still water: - Speed in still water = (Speed downstream + Speed upstream) / 2 = (30 km/h + 20 km/h) / 2 = 50 km/h / 2 = 25 km/h

Therefore, the boat's speed in still water is 25 km/h.