Question

→ 11/12 Поїзд проїхав 2км зі швидкістю 72 км/год. Скільки коливань здійснив у кабіні машиніста за час руху поїзда маятник, якщо частота його коливань 0,2 Гц? N= 11:25 Зберегти і перейти далі​

Answer 1

Ответ:

Объяснение:

S = 2км = 2000 м

V = 72 км/год = 20 м/с

f =  0,2 Гц

n = ?

t = S / V = 2000 / 20 = 100 c

n = f*t = 0.2*100 = 20 колебаний

Answer 2

To find the number of oscillations made by the pendulum in the train cabin, we can use the formula:

Number of oscillations = (Speed of train / Length of pendulum) x Time

Given: - Distance traveled by the train = 2 km - Speed of the train = 72 km/h - Frequency of oscillations of the pendulum = 0.2 Hz

To find the number of oscillations, we need to determine the length of the pendulum. Unfortunately, the length of the pendulum is not provided in the question. Without this information, it is not possible to calculate the number of oscillations made by the pendulum in the train cabin.

If you have any additional information or if there is anything else I can assist you with, please let me know!