Question

Рух тіла задано рівнянням x=0,5 + 5t -2t^2 визнвчте переміщення за 2с і швидкість руху через 3с

Answer 1

Ответ:

х(2)=2.5м V(3)=-7м/с^2

Объяснение:

x(2)=0.5+5*2-2*2^2=2.5 м

V(3)=5-4*3=-7м/с^2

Answer 2

I can help you with your physics question. The user's message is in Ukrainian and it means: "Answer in detail. The motion of a body is given by the equation x=0.5+5t-2t^2. Determine the displacement in 2s and the speed of motion after 3s."

To solve this problem, we need to use the formulas for displacement and velocity of a uniformly accelerated motion. The displacement is given by $$s=x-x_0$$, where $$x$$ and $$x_0$$ are the positions of the body at the final and initial time, respectively. The velocity is given by $$v=v_0+at$$, where $$v_0$$ is the initial velocity and $$a$$ is the acceleration.

We can find the initial position and velocity by plugging $$t=0$$ into the given equation. We get $$x_0=0.5$$ and $$v_0=5$$. The acceleration is the coefficient of $$t^2$$, which is $$-2$$.

To find the displacement in 2s, we need to find the position of the body at $$t=2$$ and subtract the initial position. We get $$x=0.5+5(2)-2(2)^2=6$$ and $$s=6-0.5=5.5$$. The displacement in 2s is 5.5 m.

To find the speed of motion after 3s, we need to find the velocity of the body at $$t=3$$ using the formula for velocity. We get $$v=5-2(3)=-1$$. The speed of motion after 3s is 1 m/s in the opposite direction of the initial velocity.

You can find more information about uniformly accelerated motion and how to solve similar problems on this website.

I hope this helps you understand the problem. If you have any other questions, feel free to ask me.

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