Question

Найдите жесткость пружины, которая под действием силы в 10 Н удлинилась на 5см​

Answer 1

Ответ:

F=kx

k=F/х

k=10/0.05=200

Answer 2

Calculation of Spring Constant

To find the spring constant (k) of a spring that elongates by 5 cm under the action of a force of 10 N, we can use Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

The formula for Hooke's Law is:

F = k * x

Where: - F is the force applied to the spring (10 N in this case) - k is the spring constant (to be determined) - x is the displacement of the spring (5 cm or 0.05 m in this case)

To find the spring constant, we can rearrange the formula:

k = F / x

Substituting the given values:

k = 10 N / 0.05 m

Calculating the value:

k = 200 N/m

Therefore, the spring constant of the given spring is 200 N/m.