Question

надувная лодка массой 5кг плавает в воде. вычисли минимальный объем подводной части надувной лодки, чтобы удержать в воде рыбалова весом 420Н.​

Answer 1

Ответ:

0,047м3

Объяснение:

Answer 2

Calculating the Minimum Submerged Volume of an Inflatable Boat

To calculate the minimum submerged volume of an inflatable boat required to support a fisherman weighing 420N, we can use the principle of buoyancy. The buoyant force acting on the boat must be equal to or greater than the weight of the fisherman for the boat to stay afloat.

Buoyant Force Calculation

The buoyant force acting on the boat can be calculated using the formula:

Buoyant force = Weight of the fluid displaced

In this case, the fluid is water, and the weight of the fisherman is 420N.

Minimum Submerged Volume Calculation

The minimum submerged volume of the boat can be calculated using the formula:

Volume = Weight of the fisherman / Density of water

The density of water is approximately 1000 kg/m^3.

Calculation

Using the given weight of the fisherman (420N) and the density of water (1000 kg/m^3), we can calculate the minimum submerged volume of the boat.

Volume = 420N / 1000 kg/m^3

Volume ≈ 0.42 m^3

Therefore, the minimum submerged volume of the inflatable boat required to support a fisherman weighing 420N in water is approximately 0.42 cubic meters.